FOCUSED PRACTICE
SAT exponential growth practice
Distinguish multiplying by a factor from adding a fixed amount, then interpret the model in context.
The idea to remember
For y = a(b)ˣ, a is the starting value and b is the factor per step. A 20% increase means b = 1.20, not 0.20.
A worked example
A model P = 100(1.2)ᵗ gives P = 144 after two steps because 100 × 1.2 × 1.2 = 144. Adding 20 twice would incorrectly give 140.
A common trap
The growth factor includes the original 100%. A decay of 15% keeps 85%, giving a factor of 0.85.
For a longer walkthrough, read Read SAT tables, slopes, and growth models with confidence.
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All 8 questions, with explanations
Work on paper or read at your own pace. Open each explanation after choosing an answer. These are the same original questions used in the interactive tool.
1. A population is modeled by P(t) = 80(1.5)ᵗ. What is the population predicted by this model when t = 2?
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Answer: A. 180
Substitute t = 2: P(2) = 80 × 1.5² = 80 × 2.25 = 180. Apply the multiplier twice. Doubling the initial value would represent a different model.
2. A machine has value V(t) = 8000(0.9)ᵗ dollars after t years. By what percent does its value decrease each year?
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Answer: D. 10%
The factor 0.9 means the machine keeps 90% of its value each year. The decrease is 100% - 90% = 10%. The initial value does not determine the percentage decrease.
3. A population is modeled by P(t) = 120(1.5)ᵗ. What is the population predicted by this model when t = 2?
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Answer: C. 270
Substitute t = 2: P(2) = 120 × 1.5² = 120 × 2.25 = 270. Apply the multiplier twice. Doubling the initial value would represent a different model.
4. A machine has value V(t) = 12000(0.85)ᵗ dollars after t years. By what percent does its value decrease each year?
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Answer: B. 15%
The factor 0.85 means the machine keeps 85% of its value each year. The decrease is 100% - 85% = 15%. The initial value does not determine the percentage decrease.
5. A population is modeled by P(t) = 160(1.5)ᵗ. What is the population predicted by this model when t = 2?
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Answer: A. 360
Substitute t = 2: P(2) = 160 × 1.5² = 160 × 2.25 = 360. Apply the multiplier twice. Doubling the initial value would represent a different model.
6. A machine has value V(t) = 16000(0.8)ᵗ dollars after t years. By what percent does its value decrease each year?
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Answer: D. 20%
The factor 0.8 means the machine keeps 80% of its value each year. The decrease is 100% - 80% = 20%. The initial value does not determine the percentage decrease.
7. A population is modeled by P(t) = 200(1.5)ᵗ. What is the population predicted by this model when t = 2?
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Answer: C. 450
Substitute t = 2: P(2) = 200 × 1.5² = 200 × 2.25 = 450. Apply the multiplier twice. Doubling the initial value would represent a different model.
8. A machine has value V(t) = 20000(0.75)ᵗ dollars after t years. By what percent does its value decrease each year?
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Answer: B. 25%
The factor 0.75 means the machine keeps 75% of its value each year. The decrease is 100% - 75% = 25%. The initial value does not determine the percentage decrease.
Scope reference: College Board’s section overview. Questions are independently authored and are not official exam material.
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